QuizSagar
4 years ago Like 232906
Questions 823
Contests 7
Value of 1+tan²θ is-
- sin²θ
- cos²θ
- tan²θ
- sec²θ
- sec²θ
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We know sec²θ-tan²θ=1 so
tan²θ-1=sec²θ
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sec²θ is equivalent to
- cosec²(90-θ)
- sin²(90 - θ)
- tan²(90 - θ)
- cos²(90 - θ)
- cosec²(90-θ)
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sin²θ is equivalent to
- cosec²(90-θ)
- sin²(90 - θ)
- tan²(90 - θ)
- cos²(90 - θ)
- cos²(90 - θ)
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cot²θ is equivalent to
- cosec²(90-θ)
- sin²(90 - θ)
- tan²(90 - θ)
- cos²(90 - θ)
- tan²(90 - θ)
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tan²θ is equivalent to
- cosec²(90-θ)
- sin²(90 - θ)
- cot²(90 - θ)
- cos²(90 - θ)
- cot²(90 - θ)
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If tanθ=12/9 then value of cosθ will be
- 9/12
- 9/15
- 12/15
- 15/9
- 9/15
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If tanθ=12/9 then value of cotθ will be
- 9/12
- 9/15
- 12/15
- 15/9
- 9/12
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tanθ= 1/ (cotθ)
Therefore 12/9=1/(12/9)=9/12
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If tanθ=12/9 then value of cosecθ will be
- 9/12
- 9/15
- 12/15
- 15/9
- 9/15
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Inverse of 2/8
- 8/2
- -8/2
- 2/8
- -2/8
- option4
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Additive inverse of 2/8 = -2/8. The additive inverse of a number a is the number that, when added to a, yields zero.
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