A tiger is 50 leaps of its own behind a deer. The tiger takes 5 leaps per minute to the deer's 4. If the tiger and the deer cover 8 metre and 5 metre per leap respectively, what distance in metres will the tiger have to run before it catches the deer?
- 400
- 800
- 100
- 200
- option2
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Total Distance=50 leep of tiger speed=50*8=400,
Tiger Speed=5leeps/min=5*8m=40m,
Deer Speed=4leeps/min=4*5m=20m
Time=Total Distance÷Relative speed
=400m÷(40-20)m/min=20min,
Total distance cover by Tiger is,
=Speed*Time=40m/min*20min=800m
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अमोनियम क्लोराइड का जलीय विलयन होता है
- अम्लीय
- उदासीन
- क्षारीय
- इनमें से कोई नहीं
- option3
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